Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

For Franchisee Enquiry

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

93219 24448 / 99871 78554

Mon to Sat - 10 AM to 7 PM

Ask doubt

Ask doubt

×

Queries asked on Sunday and after 7 pm from Monday to Saturday will be answered after 12 pm the next working day.

Properties Of Inverse Trigonometry

CBSE XII Science Maths Inverse Trigonometric Functions

Write in the simplest form:begin mathsize 20px style space tan to the power of negative 1 end exponent space open square brackets space 1 bevelled fraction numerator space over denominator space root index blank of space x squared minus 1 end root end fraction close square brackets comma open vertical bar space x close vertical bar greater than 1 end style

Asked by sunil2791 21st April 2017 6:58 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Solve:begin mathsize 20px style space open square brackets space 3 tan to the power of negative 1 end exponent space fraction numerator space 1 over denominator space 2 plus square root of space 3 end root end fraction close square brackets minus tan to the power of negative 1 end exponent space bevelled fraction numerator space 1 over denominator x equals tan begin display style bevelled fraction numerator blank to the power of negative 1 end exponent 1 over denominator 3 end fraction end style end fraction end style

Asked by sunil2791 21st April 2017 7:05 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Solve:begin mathsize 20px style space sin to the power of negative 1 end exponent x plus sin to the power of negative 1 end exponent y equals fraction numerator 2 straight pi over denominator 3 end fraction space comma space cos to the power of negative 1 end exponent x minus cos to the power of negative 1 end exponent y equals straight pi over 3 end style

Asked by sunil2791 21st April 2017 7:10 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Prove that begin mathsize 20px style tan to the power of negative 1 end exponent open parentheses 1 third tan 2 A close parentheses plus tan to the power of negative 1 end exponent open parentheses c o t A close parentheses plus tan to the power of negative 1 end exponent open parentheses c o t cubed A close parentheses equals 0 end style

Asked by sunil2791 21st April 2017 7:20 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Prove that begin mathsize 20px style sin open curly brackets tan to the power of negative 1 end exponent open square brackets fraction numerator 1 minus x squared over denominator 2 x end fraction close square brackets plus cos to the power of negative 1 end exponent open square brackets fraction numerator 1 minus x squared over denominator 1 plus x squared end fraction close square brackets close curly brackets equals 1 end style

Asked by sunil2791 21st April 2017 7:31 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Prove that begin mathsize 20px style 2 tan to the power of negative 1 end exponent open parentheses bevelled 1 fifth close parentheses plus s e c to the power of negative 1 end exponent open parentheses 5 bevelled fraction numerator square root of 2 over denominator 7 end fraction close parentheses plus 2 tan to the power of negative 1 end exponent open parentheses bevelled 1 over 8 close parentheses equals bevelled straight pi over 4 end style

Asked by sunil2791 21st April 2017 7:37 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Solve begin mathsize 20px style tan to the power of negative 1 end exponent open parentheses 2 x close parentheses plus tan to the power of negative 1 end exponent open parentheses 3 x close parentheses equals bevelled straight pi over 4 end style

Asked by sunil2791 21st April 2017 7:43 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Tan1/2[sin^-1 2x/1+x^2+cos^-1 1-y^2/1+y^2]=x+y/1-xy,if |x|<1,Y>0 and xy>1.

Asked by Balbir 28th April 2017 5:45 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

cos(2cos^-1 x +sin^-1 x) at x=1/5, 0<= cos^-1 x <=pi and -pi/2<=sin^-1 x<=pi/2.

Asked by Balbir 30th April 2017 9:28 AM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Solve the following equations  2 tan to the power of negative 1 space end exponent space left parenthesis cos space x right parenthesis equals space tan to the power of negative 1 end exponent space left parenthesis 2 space cos e c space x right parenthesis

Asked by Anshul 26th May 2017 6:14 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

 Solve the following equation tan to the power of negative 1 end exponent space 1 minus x divided by 1 plus x space equals 1 divided by 2 tan to the power of negative 1 end exponent space x

Asked by Anshul 26th May 2017 6:22 PM
Answered by Expert

CBSE XI Science Maths Linear Inequalities

Q-18 IS ATTACHED
 
Question Img

Asked by mahesh_udr2000 29th August 2017 3:31 PM
Answered by Expert

JEE Plances JEE (Main) Maths Inverse Trigonometric Functions

arccos((x-1)(x-5))/(X(x-2)(x-3))
Find its range

Asked by sudheerkapoor67 8th November 2017 5:41 AM
Answered by Expert

JEE Plances ALL Class Maths Inverse Trigonometric Functions

Arccot(sq.root cosa)+Arctan(sq.root cosa) equal to X than find the value of sinX

Asked by sudheerkapoor67 10th November 2017 3:55 AM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Kindly explain your answer.  

Asked by Varsneya Srinivas 9th February 2018 9:07 AM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Kindly provide the answer  

Asked by Varsneya Srinivas 15th March 2018 2:51 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

TanTsin to the power of 1 fraction numerator 1 over denominator square root of straight x squared minus 1 end root end fraction

write it in simple form

Asked by niharikapabba2605 11th June 2018 6:22 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Sin½

Asked by Suraj2000reddy5 27th January 2019 10:08 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

If a>b>c>0, Prove that  Cot^-1 [(ab+1)÷(a-b)]+ Cot^-1 [(bc+1)÷(b-c)]+Cot^-1[(ca+1)÷(c-a)]= pi 

Asked by mridulabarua05 21st February 2019 1:05 PM
Answered by Expert

JEE Main Maths Trigonometry

solve the below question

Asked by sarveshvibrantacademy 22nd March 2019 3:35 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

If a>b>c>0 then prove cot¯¹(ab+1/a-b)+cot¯¹(bc+1/b-c)+cot¯¹(ca+1/c-a)=¶

Asked by patelmanan4102002 5th August 2019 8:21 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

Answer iii part

Asked by lovemaan5500 4th January 2020 11:10 PM
Answered by Expert

CBSE XI Science Maths Trigonometric Functions

Solve question no-4

Asked by richasingh0708.bmps 23rd June 2020 10:00 PM
Answered by Expert

JEE Main Maths Trigonometry

2.

Asked by Premnerusu37 2nd August 2020 7:32 AM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

  Consider the equation . Choose the CORRECT option(s). The sum of all solutions = 0< The number of solutions = 2< The number of solution = 1< The sum of squares of all solutions = 1<

Asked by harshsharma2531 9th August 2020 9:28 AM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

tan^-1x-1/x-2+tan^-1x+1/x+2=pi/4.find value of x.   

Asked by sshas3199 23rd August 2020 9:24 PM
Answered by Expert

CBSE XII Science Maths Inverse Trigonometric Functions

tan¹x + tan¹y=π+tan¹(x+y/1-xy), xy>1;x, y>0

Asked by joymaibam38 26th December 2021 9:04 AM
Answered by Expert

JEE Main Maths Trigonometry

some

Asked by pranavpatil7386 7th February 2024 8:54 PM
Answered by Expert

JEE Main Maths Trigonometry

.

Asked by sandipan.sarma6 14th April 2024 10:27 AM
Answered by Expert

Chat with us on WhatsApp