CBSE Class 10 Answered
problem sum
Asked by sweetynam | 18 Feb, 2009, 04:28: PM
Expert Answer
Let the resistance of electric iron connected may be R.
We have R=R1||R2||R3
1/R= 1/100+1/50+1/500= (5+10+1)/500
R=31.25 ohms
Current through it,I=V/R=220/31.25=7.04 A
Answered by | 19 Feb, 2009, 01:53: AM
Application Videos
Concept Videos
CBSE 10 - Physics
Asked by khajannirwan | 27 Feb, 2024, 10:20: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by saanviyadla | 24 Jan, 2024, 07:06: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by kamalaranjanmohantymohanty5 | 06 Jan, 2024, 10:05: AM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by nandhikasugumar | 05 Oct, 2023, 04:01: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by daniya062008 | 02 Oct, 2023, 08:25: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:28: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:21: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:13: PM
ANSWERED BY EXPERT
CBSE 10 - Physics
Asked by prassanna.j | 03 Sep, 2023, 12:11: PM
ANSWERED BY EXPERT