CBSE Class 12-science Answered
probability
Asked by | 06 Sep, 2009, 11:49: AM
Expert Answer
If X denote the sum of numbers obtained when two fair dice are rolled then X can take values
2 ,3,4,5,6,7,8,9,10,11,12
Sample space of two dice rolled =
S = { (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) }
There are 36 outcomes so
P(X=2)= 1/36
P(X=3)=2/36 p(X=4)=3/36 P(X=5)=4/36 P(X=6)= 5/36 P(X=7)=6/36 P(X=8)=5/36 P(X=9)=4/36 P(X=10)=3/36 P(X=11)=2/36 P(x=12)= 1/36
Now calculate E(x)= xP(X=x) =7
Var X= E(X2) -E(X)2
Stand deviation = sqrt of Var (X)
Answered by | 07 Sep, 2009, 01:10: PM
CBSE 12-science - Maths
Asked by deepak.embedded | 25 Mar, 2010, 10:08: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by deepak.embedded | 25 Mar, 2010, 10:06: PM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 12 Mar, 2010, 07:30: AM
ANSWERED BY EXPERT
CBSE 12-science - Maths
Asked by | 12 Mar, 2010, 07:22: AM
ANSWERED BY EXPERT