ICSE Class 10 Answered
Preeti has a recurring deposit account of Rs 1000 per month at 10% per annum. If she gets Rs 5550 as interest at the time of maturity, find the total time for which the account was held.
Asked by mahesh.nankar | 25 Mar, 2019, 07:39: PM
Expert Answer
Recurring deposit interest I is given by,
I = p×[ n(n+1)/(2×12) ] (r/100) .............. (1)
where p is monthly contribution, p = Rs. 1000 ,
n = number of months,
r = rate of interest = 10%
and I = interest = Rs.5550
hence by substituting the values in eqn.(1) we get
1000×[ n(n+1)/24 ]×(10/100) = 5550 or n(n+1) = (24/100)×5550 = 1332
hence, n2 +n -1332 = (n+37) (n-36) = 0 hence number of months = 36
Answered by Thiyagarajan K | 25 Mar, 2019, 08:32: PM
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