Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

 pqrs is a quadrilateral .a line through s parallel to pr meets qr produced in x show that ar pqrs ={triangle pxq}

Asked by Muralivenkatavarathan 11th April 2017, 5:55 PM
Answered by Expert
Answer:

 

ΔPRS and ΔPRX are on the same base PR and between the same parallels as PR is parallel to SX.

So, ar(ΔPRS) = ar(ΔPRX)

On adding ar(ΔPQR) to both sides, we get

ar(ΔPRX) + ar(ΔPQR) = ar(ΔPRS) + ar(ΔPQR)

ar(ΔPQX) = ar(quad. PQRS)

Answered by Expert 11th April 2017, 6:02 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp