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NEET Class neet Answered

  Potential gradient along the potentiometer wire is 6 mV/cm. The balancing length for a cell of emf 1.5 V will be----- 1) 150  2) 250  3) 200  4)300
Asked by chetansathe64 | 29 Jun, 2020, 10:32: PM
answered-by-expert Expert Answer
E equals p o t e n t i a l space g r a d i e n t cross times space b a l a n c i n g space l e n g t h
1.5 equals 6 cross times 10 to the power of negative 3 end exponent cross times l e n g t h
l e n g t h equals fraction numerator 1.5 over denominator 6 cross times 10 to the power of negative 3 end exponent end fraction
l e n g t h equals 1500 over 6
l e n g t h equals 250 c m
Answered by Utkarsh Lokhande | 30 Jun, 2020, 12:00: PM
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