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CBSE Class 12-science Answered

potential energy of a dipole in a uniformly charged field
Asked by ap996969 | 18 Feb, 2019, 11:23: PM
answered-by-expert Expert Answer
Electric potential at P is given by  begin mathsize 12px style V space equals space fraction numerator 1 over denominator 4 πε subscript 0 end fraction fraction numerator p with rightwards arrow on top space times space r with hat on top over denominator r squared end fraction space end style
where begin mathsize 12px style p with rightwards arrow on top end style is electric dipole moment and begin mathsize 12px style r with hat on top space end styleis th unit vector along the direction OP.
 
At axial direction ,  begin mathsize 12px style V space equals space fraction numerator 1 over denominator 4 πε subscript 0 end fraction p over r squared space end style
At equtorial point V = 0
 
Answered by Thiyagarajan K | 20 Feb, 2019, 12:22: PM

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CBSE 12-science - Physics
A dumbbell consists of two masses A and B each of mass m joined by a light rod of length l with mass B attached to a suspension point O by a light rod of length l as shown in figure. Find the minimum required speed with which mass A to be projected horizontally so that the system completes the vertical circular motion.
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CBSE 12-science - Physics
What is charge?
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CBSE 12-science - Physics
please resolve with good explanation
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what are ghost particles please answer how is that not able to interact with other subatomic particles ..?is that faster than photons?
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CBSE 12-science - Physics
if breakdown voltage of each capacitor is 40v ,then maximum applied voltage Vmax will be
Asked by aishaisha091098 | 19 Apr, 2024, 04:54: PM
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CBSE 12-science - Physics
explain
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CBSE 12-science - Physics
solve option e
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Asked by dasrituparna1999 | 13 Apr, 2024, 06:56: AM
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CBSE 12-science - Physics
The number of moles in an elemental sample is just the ratio of the mass m to atomic mass 4. n= A The number of protons N, in an elemental sample is Z (atomic number) times the number of moles of Avogadro's number NA N=ZnN P A Copper has an atomic mass of 63.5 g/mole and 29 protons per atom. If such an atom were neutral, then it would have as many protons as electrons. If you remove electrons from a neutral state, then you get a net positive charge. Given a 54 gram ball of copper with a net charge of 2.2 µC, what fraction of the copper's electrons have been removed?
Asked by dasrituparna1999 | 12 Apr, 2024, 09:26: PM
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CBSE 12-science - Physics
which answer is correct and most appropriate with explanation
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Asked by mishrigupta19319 | 08 Apr, 2024, 06:28: PM
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CBSE 12-science - Physics
8212
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