Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days
8104911739
For Business Enquiry

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

POINTS P, Q and R are in vertical line such that PQ = QR. A ball at the top most point 'P' is allowed to fall freely. What is the ratio of the times of descent through PQ and QR?

Asked by Ayush Pateria 16th January 2011, 10:48 PM
Answered by Expert
Answer:
Dear Student,
We'll use s = ut + at2/2.
PQ = gtPQ2/2 ... (1)
For QR, u is not zero but, gtPQ.
QR = gtPQ.tQR + gtQR2/2   ... (2)
Since PQ = QR,
gtPQ2/2 = gtPQ.tQR + gtQR2/2 
tPQ /tQR = 2 + tQR /tPQ
 
Let tPQ /tQR = x
x = 2 + 1/x
x - 1/x = 2
x2 -2x - 1 = 0
x = 1 + √2
tPQ /tQR = 1 + √2 = 2.414.
regards,
Team,
TopperLearning.
Answered by Expert 17th January 2011, 10:11 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Latest Questions

CBSE X Mathematics
qsnImg
Asked by adityaagrawal020503 21st February 2019, 11:30 PM
CBSE VIII Science
Asked by suveer20052411 21st February 2019, 11:09 PM
IIT JEE Main Chemistry
qsnImg
Asked by shobhit 21st February 2019, 11:06 PM

Chat with us on WhatsApp