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plzzzzzzz ans. the question

Asked by prasadnidhi 24th May 2010, 4:06 PM
Answered by Expert
Answer:

 sec4θ (1-sin4θ) - 2tan2θ =

sec4θ (1-sin2θ)(1+sin2θ) - 2tan2θ =

sec4θ (cos2θ)(1+sin2θ) - 2tan2θ =

sec2θ (1+sin2θ) - 2tan2θ =

sec2θ + tan2θ - 2tan2θ =

sec2θ  - tan2θ = 1                   ... since  sec2θ = 1 + tan2θ

Regards,

Team,

TopperLearning.

Answered by Expert 24th May 2010, 5:30 PM
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