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Asked by prasadnidhi 24th May 2010, 4:42 PM
Answered by Expert
Answer:

 In case of multiple questions within a query, please post each question individually and let us know where you are getting stuck so that we would be able to explain things better.

2/  (1+tanθ + cotθ) (sinθ-cosθ) =(secθ/cosec2θ - cosecθ/sec2θ)

RHS =

(secθ/cosec2θ - cosecθ/sec2θ) =

(sec3θ -cosec3θ)/ cosec2θsec2θ =

(secθ -cosecθ)((sec2θ +secθ cosecθ + cosec2θ)/ cosec2θsec2θ =

Converting sec and cosec's into sin and cos,

[{(sinθ -cosθ)/(sinθcosθ)}{(tanθ +1 + cotθ)/(sinθcosθ)}]/ cosec2θsec2θ =

[{(sinθ -cosθ)(tanθ +1 + cotθ)}/(sinθcosθ)2]/ cosec2θsec2θ =

(sinθ -cosθ)(tanθ +1 + cotθ) = LHS.

Regards,

Team,

TopperLearning.  

 

Answered by Expert 24th May 2010, 5:46 PM
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