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CBSE Class 11-science Answered

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Asked by ABHILASHA | 18 Feb, 2020, 07:03: PM
answered-by-expert Expert Answer
begin mathsize 14px style d i s p l a c e m e n t space space x left parenthesis t right parenthesis space equals space t to the power of 3 to the power of space end exponent space minus 2 space t space space minus 10
v e l o c i t y space v left parenthesis t right parenthesis space equals space space fraction numerator d over denominator d t end fraction x left parenthesis t right parenthesis space equals space 3 t to the power of 2 to the power of space end exponent minus 2
a c c e l e r e a t i o n space a left parenthesis t right parenthesis space equals space fraction numerator d over denominator d t end fraction v left parenthesis t right parenthesis space equals space 6 t
F o r c e space equals space m a s s space cross times space a c c e l e r a t i o n space equals space 10 space cross times 6 t space equals space 60 space t end style
 
Hence force F at t=4s  is given by,  F = 60×4 = 240 N
Answered by Thiyagarajan K | 19 Feb, 2020, 09:04: AM
CBSE 11-science - Physics
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