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Plz solve this?

Asked by dasratna_72 1st July 2017, 7:52 PM
Answered by Expert
Answer:
begin mathsize 16px style fraction numerator sec 8 straight A minus 1 over denominator sec 4 straight A minus 1 end fraction
equals fraction numerator begin display style fraction numerator 1 over denominator cos 8 straight A end fraction end style minus 1 over denominator begin display style fraction numerator 1 over denominator cos 4 straight A end fraction end style minus 1 end fraction
equals fraction numerator 1 minus cos 8 straight A over denominator 1 minus cos 4 straight A end fraction cross times fraction numerator cos 4 straight A over denominator cos 8 straight A end fraction
equals fraction numerator 2 sin squared 4 straight A over denominator 2 sin squared 2 straight A end fraction cross times fraction numerator cos 4 straight A over denominator cos 8 straight A end fraction
equals fraction numerator open parentheses 2 sin 4 straight A space cos 4 straight A close parentheses over denominator 2 sin squared 2 straight A end fraction cross times fraction numerator sin 4 straight A over denominator cos 8 straight A end fraction

equals fraction numerator sin 8 straight A over denominator cos 8 straight A end fraction cross times fraction numerator sin 4 straight A over denominator 2 sin squared 2 straight A end fraction
equals fraction numerator sin 8 straight A over denominator cos 8 straight A end fraction cross times fraction numerator 2 sin 2 straight A space cos 2 straight A over denominator 2 sin squared 2 straight A end fraction
equals tan 8 straight A space cross times fraction numerator cos 2 straight A over denominator sin 2 straight A end fraction
equals tan 8 straight A cross times cot 2 straight A
equals fraction numerator tan 8 straight A over denominator tan 2 straight A end fraction end style
Answered by Expert 2nd July 2017, 6:50 PM
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