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Home / Doubts and Solutions/JEE/Physics

Plz solve this?

Asked by dasratna_72 11th May 2017, 3:53 PM
Answered by Expert
Answer:
The resultant forces acting on a particle in static equilibrium is zero.
F1 + F2 + F3 = 0
begin mathsize 12px style Given space that space stack straight F subscript 1 with rightwards arrow on top equals open parentheses 2 straight i with hat on top plus 3 straight j with hat on top close parentheses space and space stack straight F subscript 2 with rightwards arrow on top equals open parentheses 2 straight j with hat on top plus 2 straight k with hat on top close parentheses space rightwards arrow stack straight F subscript 1 with rightwards arrow on top space plus space stack straight F subscript 2 with rightwards arrow on top space plus stack straight F subscript 3 with rightwards arrow on top space equals space 0 rightwards arrow open parentheses 2 straight i with hat on top plus 3 straight j with hat on top close parentheses space plus space open parentheses 2 straight j with hat on top plus 2 straight k with hat on top close parentheses space plus stack straight F subscript 3 with rightwards arrow on top space equals space 0 rightwards arrow open parentheses 2 straight i with hat on top plus 5 straight j with hat on top space plus space 2 straight k with hat on top close parentheses space plus stack straight F subscript 3 with rightwards arrow on top space equals space 0 therefore stack straight F subscript 3 with rightwards arrow on top space equals open parentheses negative 2 straight i with hat on top minus 5 straight j with hat on top space minus space 2 straight k with hat on top close parentheses space straight N end style
Answered by Expert 12th May 2017, 11:57 AM
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