JEE Class main Answered
plz solve the below three questions
Asked by sarveshvibrantacademy | 22 Mar, 2019, 10:47: AM
Expert Answer
(4) In the given pressure variation graph, pressure variation is maximum at both ends.
Hence both ends are Antinodes. Hence Both ends are closed.
(5) Distance between successive antinodes is λ/2 .
For vibrations between closed ends λ = (2L)/n , where L is length of tube and n = 1,2,3...
If n =1, mode is fundamental and λ = 2L or length of tube is λ/2. Hence the mode shown in figure is fundamental.
(6) when pressure variation is maximum, displacement of air particles is minimum.
Hence at both ends displacement is minimum. Also at node diplacement of air particles is minimum.
Hence graph-(C) shows the correct variation of displacement along the horizontal distance
Answered by Thiyagarajan K | 22 Mar, 2019, 03:35: PM
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