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CBSE Class 12-science Answered

Plz solve no 4
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Asked by Ranjan | 01 May, 2018, 11:44: PM
answered-by-expert Expert Answer
Drift velocity vd = I/(neA); where I is current, n is electron number density, e is charge of electron and A is area of cross section.
 
we have to find number density;-
 
given :- density 9000 kg/m3
 
number of Cu atoms in 9000 kg = [ 6.02×1023 /(63.5×10-3) ] × 9000 = 8.54 × 1028 m-3
 
hence vd = 1.5/(8.54×1028×1.602×10-19×10-7) = 10-3 m/s = 1 mm / s
Answered by Thiyagarajan K | 02 May, 2018, 02:58: PM

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CBSE 12-science - Physics
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