Plz solve it step by step making me understand the formula being applied here
Asked by vishakhachandan026
23rd July 2019,
8:59 AM
Answered by Expert
Answer:
Fig.1 shows two rods which are inclined to vertical axis by 45°. Let length of each rod be l and mass of each rod be m.
Let us consider moment of inertial of small mass elements dm from both the rods,
which is of length dl' and at a distance l' from point O.
Moment of inertia dI about the axis passing through centre as shown in fig.1 is given by
dI = 2×dm×(l'/√2)2 = ( ρ×dl' )×(l')2
where ρ is mass of rod per unit length.
Moment of inertia I of system of two rods about the axis passing through centre as shown in fig. 1 is given by
......................(1)Moment of inertia I of system of four rods about the axis passing through centre as shown in fig. 2 is given by
I = m×(2/3)×l2 ...........................(2)
Moment of inertia I of system of four rods about the axis passing through corner as shown in fig. 3 is obtained
by applying parallel axis theorem.
Hence, noment of inertia I = m×(2/3)×l2 + 4m×(l/√2)2 = (8/3)m×l2
Answered by Expert
23rd July 2019,
2:30 PM
Rate this answer
- 1
- 2
- 3
- 4
- 5
- 6
- 7
- 8
- 9
- 10
You have rated this answer /10
Your answer has been posted successfully!
RELATED STUDY RESOURCES :
Browse free questions and answers by Chapters
- 1 Thermodynamics
- 2 Gravitation
- 3 Electromagnetic Waves
- 4 Communication Systems
- 5 Laws of Motion
- 6 Current Electricity
- 7 Work, Energy and Power
- 8 Kinematics
- 9 Physics and Measurement
- 10 Rotational Motion
- 11 Properties of Solids and Liquids
- 12 Kinetic Theory of Gases
- 13 Oscillations and Waves
- 14 Electrostatics
- 15 Magnetic Effects of Current and Magnetism
- 16 Electromagnetic Induction and Alternating Currents
- 17 Optics
- 18 Dual Nature of Matter and Radiation
- 19 Atoms and Nuclei
- 20 Electronic Devices
Trending Tags
Latest Questions
JEE Main Mathematics
Asked by amaladelsingh
28th October 2020,
10:24 PM
CBSE X Biology
Asked by reenacharan2008
28th October 2020,
9:11 PM
