CBSE Class 11-science Answered
Plz solve it fast
Asked by rajdhan.yadav187350 | 02 Oct, 2018, 01:30: PM
Expert Answer
if the 20N force is acting towards north on a 10 kg mass, then acceleration is 20/10 = 2 m/s2 .
displacement Sn in north direction after 2 sec will be determined by the formula Sn = (1/2)×a×t2 ,
since initial velocity towards north direction is zero. a is acceleration and t is time.
Sn = (1/2)×2×22 = 4 m/s
velocity component along east direction is unaffected. hence displacement Se in east direction after 2 second is given by, Se = 2×2 = 4 m/s
resultant displacement as shown in figure = 4√2 m/s
Answered by Thiyagarajan K | 03 Oct, 2018, 01:10: AM
CBSE 11-science - Physics
Asked by sheikhsaadat24 | 17 Apr, 2024, 09:41: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sy123946 | 07 Apr, 2024, 04:23: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by derhebha955 | 03 Apr, 2024, 09:03: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 29 Mar, 2024, 05:15: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by sumedhasingh238 | 28 Mar, 2024, 11:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by emad.amd | 21 Mar, 2024, 12:00: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by om636694 | 04 Mar, 2024, 09:10: PM
ANSWERED BY EXPERTCBSE 11-science - Physics
Asked by rajuinwati12 | 04 Mar, 2024, 09:22: AM
ANSWERED BY EXPERT
