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# Plz help me with these .

Asked by 25th February 2013, 8:10 PM
1) Let two circles having their centres as O and O' intersect each other at point A and B respectively. Let us join OO'

In triangle (AOO') and triangle(BOO'),
OA = OB (Radius of first circle)
O'A = O'B (Radius of second circle)
OO' = OO' (Common)
Hence, triangle (AOO') is congruent to triangle(BOO'), (By SSS)
?OAO' = ? OBO' (By CPCT)
Therefore, line of centres of two intersecting circles subtends equal angles at the two points of intersection.

2. Let ABCD be the square with side s and diagonal AC = 10 cm
Since triangle ABC is a right angled triangle, therefore by pythagoras theorem we have

AB2 + BC2  = AC2
s2 + s2 = 102
2s2 = 100
s2 = 50
Area of a square = s2 = 50 cm2
Answered by Expert 26th February 2013, 5:58 AM
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