CBSE Class 10 Answered
plz answer soon tomorrow is exam plzzzzzzzzzzz
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
Expert Answer
Please post queries individually.
Solution to Q 6 of Exercise 12.3 of NCERT.
R = 32 cm
The side of an equilateral triangle circumscribed in a circle of radius R, is given by,
2Rsin(60)
Area of the equilateral triangle = (
3/4)side2
= (3/4)(4x32x32x3/4)
= 1330.17 cm2
Area of circle = 3.14x32x32 = 3215.36 cm2
Area of design = Area of circle - Area of triangle = 3215.36 - 1330.17 = 1885.2 cm2
Regards,
Team,
TopperLearning.
Answered by | 10 Mar, 2010, 03:31: PM
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