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Home / Doubts and Solutions/JEE/Mathematics

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Asked by g_archanasharma 10th April 2018, 10:14 AM
Answered by Expert
Answer:
begin mathsize 16px style straight x cubed minus open parentheses straight a plus 1 close parentheses straight x squared plus open parentheses straight b minus straight a close parentheses straight x minus straight b equals 0 tanα comma space tanβ space and space tanγ space are space the space roots space of space the space equation. tanα plus tanβ plus tanγ equals fraction numerator negative open square brackets negative open parentheses straight a plus 1 close parentheses close square brackets over denominator 1 end fraction equals straight a plus 1 tanαtanβ plus tanβtanγ plus tanαtanγ equals fraction numerator straight b minus straight a over denominator 1 end fraction equals straight b minus straight a tanαtanβtanγ equals fraction numerator negative open parentheses negative straight b close parentheses over denominator 1 end fraction equals straight b Put space it space in space tan open parentheses straight alpha plus straight beta plus straight gamma close parentheses equals fraction numerator tanα plus tanβ plus tanγ minus tanαtanβtanγ over denominator tanαtanβ plus tanβtanγ plus tanαtanγ minus 1 end fraction you space will space get tan open parentheses straight alpha plus straight beta plus straight gamma close parentheses equals fraction numerator straight a plus 1 minus straight b over denominator straight b minus straight a plus 1 end fraction tan open parentheses straight alpha plus straight beta plus straight gamma close parentheses equals negative 1 straight alpha plus straight beta plus straight gamma equals straight pi minus straight pi over 4 equals fraction numerator 3 straight pi over denominator 4 end fraction end style
Answered by Expert 10th April 2018, 3:01 PM
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