Ask a Doubt
Request a call back

Join NOW to get access to exclusive study material for best results

NEET Class neet Answered

Pls solving the follin
question image
Asked by ntg432000 | 28 Apr, 2019, 04:25: PM
answered-by-expert Expert Answer
Q. 79.
 
Given:
 
Mass = 15 g
 
Volume = 500 ml
 
We know,
 
straight M space equals space straight pi over RT space space space equals fraction numerator 6.41 over denominator 0.082 cross times 298 end fraction space space space equals space 0.262 space straight M
 
Therefore, 0.262 mol of particles present in 1 litre of solution and 0.131 mol of particles present in 500 ml of solution.
 
Each mole of sucrose gives 1 mol of particles.
Each mole of NaCl gives 2moles of particals.
 
Consider,
Mass of C12H22O11 be X g and
 
Mass of NaCl is (15 - X) g 
 
No space of space moles space equals space fraction numerator Mass space over denominator Molar space mass end fraction space space space space space space space space 0.131 space space equals space fraction numerator straight X over denominator 342.3 end fraction plus space fraction numerator 2 open parentheses 15 minus straight X close parentheses over denominator 58.44 end fraction space space space space space space space space space space space 0.131 space space equals fraction numerator space 58.44 open parentheses straight X close parentheses space plus space space open parentheses 342.3 close parentheses cross times 2 open parentheses 15 minus straight X close parentheses space space space space over denominator 342.3 cross times 58.44 end fraction space space space space space space space space space space space space 0.131 space space equals space space fraction numerator 58.44 straight X space plus 10269 space minus space 684.6 straight X over denominator 20004.01 end fraction space space space space space space space space space space 2620.5 space equals space minus 626.16 straight x plus 10269 space space space space space space space space minus 7648.5 space equals space minus 626.16 straight x space space space space space space space space space space space space space space space space space straight X space equals space fraction numerator 7648.5 over denominator 626.16 end fraction space space space space space space space space space space space space space space space space straight X space equals space 12.21 space straight g space space space space space therefore space Sucrose space equals space 12.21 space straight g Pecentage space of space sucrose comma space space space space space space space space space space space space space space fraction numerator 12.2 over denominator 15 end fraction cross times 100 space space space space space space space space space space space space space equals space 81.42 space percent sign space sucrose For space NaCl comma 100 space minus 81.42 equals space 18.57 space percent sign space of space NaCl space space 
 
Pertange composition,
 
Sucrose is 81.42 %
 
NaCl is 18.57%
Answered by Varsha | 29 Apr, 2019, 02:33: PM

Concept Videos

Multiple Choice Questions Practice Test
Answered Unanswered My Questions My Answers
NEET neet - Chemistry
solutions
question image
Asked by 8239682116rahul | 10 Apr, 2024, 01:48: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
The specific conductance of N/10 kcl solution at 20°C is 0.0212ohm–1 cm–1 and the resistance of the cell containing this solution at 20°C is 55ohm the cell constant
Asked by ramadevisupriya5678 | 28 Mar, 2024, 02:18: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
physics
question image
Asked by kavyamodi237 | 11 Jul, 2022, 06:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
Why vacuum pump is inserted in the final collecting beaker and not in the first flask (in which the two liquids are present initially) in distillation under reduced pressure process?
Asked by myindiaisbad | 17 Jun, 2022, 11:17: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
chemistry
question image
Asked by bhaveshkaria31 | 30 May, 2022, 09:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
the boiling point of 0.15 molar aqueous solution of an unknown solute is 373.23 K at 1 atm . The molal elevatio constant of water is ______ K kg mol ^(-1)
Asked by rautganesh2255 | 01 Jul, 2021, 09:32: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
show that total vapour pressure over the solution of two liquids 1&2 at a particular temperature varies linearly with the mole fraction of a components
Asked by NituBarman192 | 01 Jun, 2021, 10:22: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
What is the solution sir ?
question image
Asked by bhagirathdangi12345 | 12 Feb, 2021, 01:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
Please explain this
question image
Asked by akashmanu09 | 08 Jan, 2021, 10:21: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
NEET neet - Chemistry
What are protic and aproticsolutions 
Asked by arnavvidudala20050 | 17 May, 2020, 03:07: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
My Class Videos Tests ₹ Plans Ask a Doubt
Get Latest Study Material for Academic year 24-25 Click here
×