Pls solve
Asked by g_archanasharma
24th March 2018,
5:22 PM
Answered by Expert
Answer:
left side figure shows the position of detector to get maximum intensity. The detector is at a distance λ/2 from wall to get constructive interference of incident and reflected wave. Right side figure shows the location of detectro to get minimum intesity. The detector is at a distance 3λ/4 from wall to get destructive interference. Hence the minimum distance to be moved is (3λ/4) - (λ/2) = λ/4
λ = 330/660 = 0.5 m
Hence the distance to be moved is 0.5/4 = 0.125 m
Answered by Expert
25th March 2018,
4:45 PM
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