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Pls solve this question with proper explanation.  Answer each part separately. 
question image
Asked by riyamaths | 09 Sep, 2018, 07:51: PM
answered-by-expert Expert Answer
As shown in figure, getting the equivalent resistance in the circuit is explained below:
 
Step-1 :- R2 and R4 are in series. Resistance of this series combination is 15Ω + 15Ω = 30Ω.

Step-2 :- Series combination of (R2+R4) is parallel with R3. Hence equivalent resistance of R2, R3 and R4 is (30×20)/(30+20) = 12Ω

Step-3 :- as shown in step-2, resistances 20Ω, 12Ω and 8Ω are in series. Hence Equivalent resistance is 20+12+8 = 40Ω.
 
Total current drawn from battery = 12/40 = 0.3 A
 
(i) current through R1 = 20Ω is 0.3 A, voltage drop across R1 is 20×0.3 = 6 V

(ii) current through R5 = 8Ω is 0.3 A, voltage drop across R5 is 8×0.3 = 2.4 V

(iii) As shown in step-2, resistance between A and B is 12Ω and 0.3A is passing through it.
        Hence  voltage drop across A and B is 12×0.3 = 3.6V. Hence voltage drop across resistance R3 is 3.6V.
        Hence current passing through R3 is 3.6/20 = 0.18A

(iv) If 0.18A is passing through R3 and total current drawn from battery is 0.3A, then 0.12A is passing through R2 and R4.
       Voltage drop across R2 is 15×0.12 = 1.8V . Voltage drop across R4 is 15×0.12 = 1.8V
Answered by Thiyagarajan K | 10 Sep, 2018, 01:34: AM

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