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Pls solve this?

Asked by dasratna_72 11th June 2017, 5:10 PM
Answered by Expert
Answer:

H-atom is exposed to UV radiation having wavelength 102.8nm


the energy of photon corresponding to 102.8 nm waveegth is


E = hc/λ = 1242 eV-nm /102.8 nm


   = 12.42 eV


The energy needed to take athe H atom frm ground state to first excited state is


                    E2-E1 - 13.6 eV - 3.4 eV = 10.2 eV


and to  the second excited state is


                    E3-E1 - 13.6 eV - 1.5 eV = 12.1 eV


and to  the third excited state is


                    E4-E1 - 13.6 eV - 0.85 eV = 12.75 eV


thus 12.42 eV photon has large probability of being absorbed in 12.1 eV


The corresponding  waveegth is: λ = 1242/12.1


                                                               =103 nm

Answered by Expert 11th June 2017, 5:32 PM
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