CBSE Class 11-science Answered
Pls solve.
Asked by pb_ckt | 18 May, 2019, 11:05: PM
Expert Answer
Option (2) is correct.
Given:
For H2SO4
M1 = 0.2 M
V1 = 100 ml
= 0.1 litre
No. of moles of H2SO4 = 0.2 × 0.1
= 0.02 moles
For NaOH
M2 = 0.5 M
V2 = 100 ml
= 0.1 litre
No. of moles of NaOH = 0.5× 0.1
= 0.05 moles
We know,
So, here H2SO4 acts as limiting reagent.
Therefore, 0.02 moles of H2SO4 will give,
Mass of salt produced is 2.84 gm.
Answered by Varsha | 20 May, 2019, 03:14: PM
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