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CBSE Class 11-science Answered

Pls solve it.
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Asked by pb_ckt | 16 May, 2019, 03:44: PM
answered-by-expert Expert Answer
The correct option is (2)
 
Given:
 
2 moles of each N2 , H2 and NH3 is present.
 
Initial weight of N2 = ?
 
Initial weight of H=?
 
The reaction is,
 
space space straight N subscript 2 space space space plus space space 3 straight H subscript 2 space space space space rightwards arrow with blank on top space space space 2 NH subscript 3
1 space mol space space space space space 3 space mol space space space space space space space space space space space space 2 space mole
 
Now, it is given that 2 moles of NH3 is formed.
From reaction it is clear that, to produce 2 moles of NH3 1 mole of N2 and 3 H2 moles of are required.
 
Also it is geven that 2 moles of N2 and H2 are remained after formation of NH3. 
 
Therefore the initial mole of  N2 = 2+1 
 
                                               = 3 mole
We know,
 
1 mole of N2 = 28 gm
 
3 moles of  of N2 =84 gm
 
Now 
the initial mole of   H2= 3+2 
 
                              = 5 mole
 
We know,
 
1 mole of H2 = 2 gm
 
5 moles of  of  H2 =10 gm
 
Therefore the initial weight of  N2 and H2 is 84 gm and 10 gm respectively.
Answered by Varsha | 17 May, 2019, 11:16: AM
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