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CBSE Class 11-science Answered

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Asked by sdmbotch1123 | 18 Jan, 2023, 11:01: PM
answered-by-expert Expert Answer
5 cosA + 3 = 0
 
cosA = -3/5  ;  hence sinA = begin mathsize 14px style square root of 1 minus open parentheses 3 over 5 close parentheses squared end root space equals space 4 over 5 end style
 
Roots of quatratic equation :- 9x2 + 27x + 20 = 0
 
begin mathsize 14px style x space equals space fraction numerator negative 27 plus-or-minus square root of left parenthesis 27 right parenthesis squared minus left parenthesis 4 cross times 9 cross times 20 right parenthesis end root over denominator 18 end fraction space equals space minus 4 over 3 space space o r space minus 5 over 3 end style
x = tanA or secA
Answered by Thiyagarajan K | 19 Jan, 2023, 07:49: AM

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