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Asked by g_archanasharma 10th April 2018, 10:12 AM
Answered by Expert
Answer:
begin mathsize 16px style open parentheses 1 plus straight x close parentheses to the power of 15 equals straight C subscript 0 plus straight C subscript 1 straight x plus straight C subscript 2 straight x squared plus........ plus straight C subscript 15 straight x to the power of 15
diff space wrt space straight x
15 open parentheses 1 plus straight x close parentheses to the power of 14 equals straight C subscript 1 plus 2 straight C subscript 2 straight x plus 3 straight C subscript 3 straight x squared plus........ plus 15 straight C subscript 15 straight x to the power of 14
put space straight x equals 1
15 cross times 2 to the power of 14 equals open parentheses straight C subscript 1 plus straight C subscript 2 plus straight C subscript 3 plus........ plus straight C subscript 15 close parentheses plus straight C subscript 2 plus 3 straight C subscript 3 plus........ plus 14 straight C subscript 15
15 cross times 2 to the power of 14 equals open parentheses 2 to the power of 15 minus 1 close parentheses plus straight C subscript 2 plus 3 straight C subscript 3 plus........ plus 14 straight C subscript 15
straight C subscript 2 plus 3 straight C subscript 3 plus........ plus 14 straight C subscript 15 equals 15 cross times 2 to the power of 14 minus 2 to the power of 15 plus 1 equals 13 cross times 2 to the power of 14 plus 1
comparing space straight lambda equals 13 comma space straight mu equals 1 end style
Answered by Expert 10th April 2018, 5:16 PM
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