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CBSE Class 12-science Answered

pls solve
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Asked by sulaikhasulu393 | 29 May, 2020, 10:00: PM
answered-by-expert Expert Answer
Linear velocity of the sphere is Vo and angular velocity about center is Vo/2R. We have to calculate the final translational velocity of the sphere when nit starts pure rolling.
A n g u l a r space v e l o c i t y equals fraction numerator V subscript 0 over denominator 2 R end fraction T r a n s l a t i o n a l space v e l o c i t y equals V subscript 0 A s space V subscript 0 greater than fraction numerator V subscript 0 over denominator 2 R end fraction comma space t h e r e space w i l l space b e space s l i p p i n g space i n i t i a l l y space a f t e r space t h a t space t h e space p u r e space r o l l i n g space s t a r t a subscript c o m end subscript equals f over m V subscript f i n a l end subscript equals u minus a subscript c t V subscript f i n a l end subscript equals v subscript 0 minus f over M t minus negative negative negative negative negative negative negative negative left parenthesis 1 right parenthesis A s space w e space k n o w capital gamma equals I alpha equals f R alpha equals fraction numerator f R over denominator begin display style 2 over 5 end style M R squared end fraction A n g u l a r space v e l o c i t y space a t t a i n e d space a f t e r space t i m e space t omega equals omega subscript 0 plus alpha t omega equals omega subscript 0 plus fraction numerator f R over denominator begin display style 2 over 5 M R squared end style end fraction t omega equals V subscript 0 over 2 plus fraction numerator f R over denominator begin display style 2 over 5 M R squared end style end fraction t omega equals fraction numerator V subscript 0 over denominator 2 R end fraction plus fraction numerator 5 f over denominator begin display style 2 M R end style end fraction t omega R equals V subscript 0 over 2 plus fraction numerator 5 f t over denominator begin display style 2 M end style end fraction minus negative negative negative negative left parenthesis 2 right parenthesis U sin g space e q u a t i o n space left parenthesis 1 right parenthesis space a n d space left parenthesis 2 right parenthesis fraction numerator 5 f over denominator 2 M end fraction t equals 5 over 2 v subscript 0 minus 5 over 2 V subscript f i n a l end subscript equals omega R minus V subscript 0 over 2 5 over 2 v subscript 0 minus 5 over 2 V subscript f i n a l end subscript equals V subscript f i n a l end subscript minus V subscript 0 over 2 3 v subscript 0 equals 7 over 2 V subscript f i n a l end subscript V subscript f i n a l end subscript equals fraction numerator 6 v subscript 0 over denominator 7 end fraction
Answered by Utkarsh Lokhande | 30 May, 2020, 11:48: AM

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CBSE 12-science - Physics
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CBSE 12-science - Physics
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The number of moles in an elemental sample is just the ratio of the mass m to atomic mass 4. n= A The number of protons N, in an elemental sample is Z (atomic number) times the number of moles of Avogadro's number NA N=ZnN P A Copper has an atomic mass of 63.5 g/mole and 29 protons per atom. If such an atom were neutral, then it would have as many protons as electrons. If you remove electrons from a neutral state, then you get a net positive charge. Given a 54 gram ball of copper with a net charge of 2.2 µC, what fraction of the copper's electrons have been removed?
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