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Asked by drpreetyshukla3 20th October 2018, 9:40 AM
Answered by Expert
Answer:
Only one question per posting is allowed. Hence we are answering question no. (8)

As per the given information we consider the locations of ship-A and Ship-B at any instant t in X-Y coordinate system as shown in figure.
 
At any instant t, coordintates of Ship-A and ship-B  are (-10t, 0), (0, 100-10t) respectively.
where t is in hours and distances are measured in km.
 
Distance S between Ship-A and Ship-B is given by, S2 = 100t2 + (100-10t)2 .................(1)
 
if we differentiate eqn.(1),  2S×(dS/dt)  = 200×t + 2×(100-10×t)×(-10) = 400×t - 2000 ...............(2)
 
distance S is mimimum, when (dS/dt) = 0. This condotion we get in eqn.(2), when t = 5 hour
Answered by Expert 21st October 2018, 11:21 PM
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