Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (North, West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

9372462318 / 9987178554

Mon to Sat - 10 AM to 7 PM

# PLS HELP IN THESE TWO QUES ALSO

Asked by drpreetyshukla3 20th October 2018, 9:40 AM
Only one question per posting is allowed. Hence we are answering question no. (8)

As per the given information we consider the locations of ship-A and Ship-B at any instant t in X-Y coordinate system as shown in figure.

At any instant t, coordintates of Ship-A and ship-B  are (-10t, 0), (0, 100-10t) respectively.
where t is in hours and distances are measured in km.

Distance S between Ship-A and Ship-B is given by, S2 = 100t2 + (100-10t)2 .................(1)

if we differentiate eqn.(1),  2S×(dS/dt)  = 200×t + 2×(100-10×t)×(-10) = 400×t - 2000 ...............(2)

distance S is mimimum, when (dS/dt) = 0. This condotion we get in eqn.(2), when t = 5 hour
Answered by Expert 21st October 2018, 11:21 PM
• 1
• 2
• 3
• 4
• 5
• 6
• 7
• 8
• 9
• 10

You have rated this answer /10