CBSE Class 11-science Answered
pls help
Asked by | 29 Sep, 2009, 11:17: PM
Expert Answer
(a) speed = distance/time = circumference/time = 2x3.14x0.02/60 = 0.002 m/s
(b) Velocity at 0 sec = 0.002i, Velocity at 15 sec = -0.002j
(since at 0 sec the clock hand is about to move in horizontal direction and at 15 sec is about to move in vertically downward direction)
(c) Change in velocity = final velocity - initial velocity = -0.002(i + j)
(d) Average acceleration in 0 to 15 sec = change in velocity/time = -0.002(i + j)/15
Regards,
Team,
TopperLearning.
Answered by | 29 Sep, 2009, 11:27: PM
Concept Videos
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by vinitdubey7735 | 14 Mar, 2024, 11:21: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by shailajakandikatla19 | 18 Jan, 2024, 06:40: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by dhanshreekansyakar | 09 Jan, 2024, 11:57: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by banhisikhapanda49 | 07 Nov, 2023, 10:42: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
in a vertical circle of radius r at what point in its path a particle may have tension equal to zero
Asked by momintaufik26 | 13 Oct, 2023, 08:26: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by anshujaiswalname | 10 Sep, 2023, 01:29: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by subhashreeojha235 | 20 Jul, 2023, 11:22: AM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by preethiprithivi05 | 21 Feb, 2023, 09:28: PM
ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by hy9022075 | 11 Jan, 2023, 05:06: PM
ANSWERED BY EXPERT