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# pls help

Asked by 29th September 2009, 11:17 PM

(a) speed = distance/time = circumference/time = 2x3.14x0.02/60 =  0.002 m/s

(b) Velocity at 0 sec = 0.002i,  Velocity at 15 sec = -0.002j

(since at 0 sec the clock hand is about to move in horizontal direction and at 15 sec is about to move in vertically downward direction)

(c) Change in velocity = final velocity - initial velocity = -0.002(i + j)

(d) Average acceleration in 0 to 15 sec = change in velocity/time = -0.002(i + j)/15

Regards,

Team,

TopperLearning.

Answered by Expert 29th September 2009, 11:27 PM
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