Request a call back

Join NOW to get access to exclusive study material for best results

CBSE Class 11-science Answered

pls help
Asked by | 29 Sep, 2009, 11:17: PM
answered-by-expert Expert Answer

(a) speed = distance/time = circumference/time = 2x3.14x0.02/60 =  0.002 m/s

(b) Velocity at 0 sec = 0.002i,  Velocity at 15 sec = -0.002j

(since at 0 sec the clock hand is about to move in horizontal direction and at 15 sec is about to move in vertically downward direction)

(c) Change in velocity = final velocity - initial velocity = -0.002(i + j)

(d) Average acceleration in 0 to 15 sec = change in velocity/time = -0.002(i + j)/15

Regards,

Team,

TopperLearning.

Answered by | 29 Sep, 2009, 11:27: PM
CBSE 11-science - Physics
Asked by roshnibudhrani88 | 23 Mar, 2024, 05:52: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by dhanshreekansyakar | 09 Jan, 2024, 11:57: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by banhisikhapanda49 | 07 Nov, 2023, 10:42: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by momintaufik26 | 13 Oct, 2023, 08:26: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by anshujaiswalname | 10 Sep, 2023, 01:29: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by subhashreeojha235 | 20 Jul, 2023, 11:22: AM
ANSWERED BY EXPERT ANSWERED BY EXPERT
CBSE 11-science - Physics
Asked by preethiprithivi05 | 21 Feb, 2023, 09:28: PM
ANSWERED BY EXPERT ANSWERED BY EXPERT
Get Latest Study Material for Academic year 24-25 Click here
×