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CBSE Class 12-science Answered

Pls give the full explanation of this!! From where it has been derived
Asked by ayushi | 13 Jun, 2016, 12:45: AM
answered-by-expert Expert Answer
Dear ayushicutiepie21@gmail.com

The question posted seems to be incomplete. Please confirm and check the first equation (equation 1) and repost your question.

However, what we could understand from your query is,
 
begin mathsize 12px style Since space the space given space equation comma straight K subscript straight t space equals negative space 2.303 space log space open parentheses fraction numerator straight P subscript infinity space minus space straight P subscript 0 over denominator straight P subscript infinity space minus space straight P subscript straight t end fraction close parentheses space space minus negative negative negative space left parenthesis 1 right parenthesis If space only space reactant space is space straight a space gas comma space then space straight P infinity space will space become space zero. space left parenthesis straight P subscript infinity space equals space 0 right parenthesis This space is space because comma space during space any space chemical space equation space certain space amount space of space pressure space is space applied. space That space is comma space your space initial space pressure space straight P subscript 0. Thus comma space infinite space pressure space becomes space negligible space and space hence space straight P subscript infinity space equals space 0.  Therefore comma space the space above space equation space left parenthesis 1 right parenthesis space becomes comma straight K subscript straight t space equals negative space 2.303 space log space open parentheses straight P subscript 0 over straight P subscript straight t close parentheses space space minus negative negative negative negative left parenthesis 2 right parenthesis If space only space product space is space straight a space gas comma space then space initial space straight P subscript 0 space becomes space 0. space left parenthesis straight P subscript 0 space equals space 0 right parenthesis comma space Therefore comma space the space above space equation space left parenthesis 1 right parenthesis space becomes comma  straight K subscript straight t space equals negative space 2.303 space log space space open parentheses fraction numerator straight P subscript infinity space over denominator straight P subscript infinity space minus space straight P subscript straight t end fraction close parentheses space minus negative negative negative left parenthesis 3 right parenthesis end style
 
Regards

Topperlearning Team.
Answered by Hanisha Vyas | 13 Jun, 2016, 05:18: PM
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