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ICSE Class 10 Answered

pls explain this as well as how to solve:A uniform metre rule rests horizontally on a knife edge at the 60 cm mark when a mass of 10 g is suspended from one end.Draw a diagram of the arrangement. a)at which end must this mass be suspended? b)what is the mass of the rule?
Asked by hrmeenal24 | 08 May, 2019, 07:12: PM
answered-by-expert Expert Answer
Figure shows the uniform meter scale rests on a knife edge placed at 60 cm mark. 
 
Weight of the scale W acts downwards at centre of gravity of scale which is at 50 cm mark
to give anticlockwise moment with respect to knife edge.
 
To counter balance this anticlockwise moment, 10 g mass is suspened at the right most edge (100 cm mark)
to give clockwise moment.
 
Anticlockwise moment of weight of scale W about knife edge = W×10   gf-cm     
Clockwise moment of suspended 10g mass about knife edge = 10×40  gf-cm
 
At equilibrium, anticlockwise moment exactly balances clockwise moment. Hence  W×10 = 10×40  ..........(1)
 
from eqn.(1), we get weight of scale W = 40 gf   or  mass of scale = 40 g
Answered by Thiyagarajan K | 08 May, 2019, 08:30: PM

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