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CBSE Class 10 Answered

pls explain
question image
Asked by gpnkumar0 | 03 Mar, 2018, 09:47: PM
answered-by-expert Expert Answer
begin mathsize 16px style fraction numerator sin squared straight theta over denominator cotθ end fraction plus fraction numerator begin display style cos squared straight theta end style over denominator begin display style tanθ end style end fraction plus 2 sinθcosθ
equals sin squared θtanθ plus cos squared θcotθ plus 2 sinθcosθ
equals open parentheses 1 minus cos squared straight theta close parentheses tanθ plus open parentheses 1 minus sin squared straight theta close parentheses cotθ plus 2 sinθcosθ
equals tanθ minus cos squared θtanθ plus cotθ minus sin squared θcotθ plus 2 sinθcosθ
equals tanθ minus cos squared straight theta cross times fraction numerator begin display style sinθ end style over denominator cos begin display style straight theta end style end fraction plus cotθ minus sin squared straight theta cross times fraction numerator begin display style cosθ end style over denominator begin display style sin straight theta end style end fraction plus 2 sinθcosθ
equals tanθ minus sinθcosθ plus cotθ minus sinθcosθ plus 2 sinθcosθ
equals tanθ plus cotθ end style
Answered by Sneha shidid | 04 Mar, 2018, 12:04: PM

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