Please wait...
1800-212-7858 (Toll Free)
9:00am - 8:00pm IST all days

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this toll free number

022-62211530

Mon to Sat - 11 AM to 8 PM

Pls Answer

Asked by sanskritforall 9th March 2010, 8:25 PM
Answered by Expert
Answer:

if

 a,b,c are three consecutive terms of an A.P.

then

b-a=c-b

2b=(a+c)

so ATQ,

2(k+5)=(2k-7)+(3k+2)

solving we get

2k+10=5k-5

15=3k

k=5

Answered by Expert 9th March 2010, 10:38 PM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp