CBSE Class 10 Answered
Pls Answer
Asked by sanskritforall | 09 Mar, 2010, 08:25: PM
Expert Answer
if
a,b,c are three consecutive terms of an A.P.
then
b-a=c-b
2b=(a+c)
so ATQ,
2(k+5)=(2k-7)+(3k+2)
solving we get
2k+10=5k-5
15=3k
k=5
Answered by | 09 Mar, 2010, 10:38: PM
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