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Pls answer the follinfi.
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Asked by ntg432000 | 25 Apr, 2019, 07:03: PM
answered-by-expert Expert Answer
As the pipe is closed at one end, the frequency of resonance is given by
f equals fraction numerator n v over denominator 4 l end fraction
l equals fraction numerator n v over denominator 4 f end fraction
Where l is the length of air coloum
Therefore, on substituting the values
l equals fraction numerator n cross times 330 over denominator 4 cross times 330 end fraction l equals n divided by 4 l equals 0.25 n l equals 25 n space space c m
n=1,3,....
 
Therefore ,
l= 25cm, 75 cm
l plus h equals 120 h equals 120 minus l h subscript m i n end subscript equals 120 minus l subscript m a x end subscript h subscript m i n end subscript equals 120 minus 75 h subscript m i n end subscript equals 45 c m
Answered by Utkarsh Lokhande | 25 Apr, 2019, 07:51: PM
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Pls answer the follinfi.
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