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Pls answer the follinfi.

qsnImg
Asked by ntg432000 25th April 2019, 7:03 PM
Answered by Expert
Answer:
As the pipe is closed at one end, the frequency of resonance is given by
f equals fraction numerator n v over denominator 4 l end fraction
l equals fraction numerator n v over denominator 4 f end fraction
Where l is the length of air coloum
Therefore, on substituting the values
l equals fraction numerator n cross times 330 over denominator 4 cross times 330 end fraction
l equals n divided by 4
l equals 0.25 n
l equals 25 n space space c m
n=1,3,....
 
Therefore ,
l= 25cm, 75 cm
l plus h equals 120
h equals 120 minus l
h subscript m i n end subscript equals 120 minus l subscript m a x end subscript
h subscript m i n end subscript equals 120 minus 75
h subscript m i n end subscript equals 45 c m
Answered by Expert 25th April 2019, 7:51 PM
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