CBSE Class 10 Answered
pls answer
Asked by Pandeyo | 31 Aug, 2009, 10:22: PM
Expert Answer
In EDC and ABC
EDC = ABC (given)
ECD is common.
By AA corollary
EDC ABC
⇒ED/ AB = CD/ BC ..............(1)
Similarly, EDB BFC
⇒ED/ FC = BD/BC ...............(2)
Adding (1) and (2)
ED/AB + ED/ FC = CD/BC + BD/BC
ED (1/AB + 1/ FC) = 1/BC (CD + BD)
Now on sunbstituting AB=x,ED=y,FC=z
y (1/x + 1/z) = 1/BC (BC)
y (1/x + 1/z) = 1
1/x + 1/z = 1/y
This is the required proof.
Answered by | 01 Sep, 2009, 09:12: AM
CBSE 10 - Maths
Asked by s.sreeram | 11 Mar, 2010, 08:14: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:24: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:08: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by BhavSimran | 10 Mar, 2010, 12:05: PM
ANSWERED BY EXPERT