CBSE Class 9 Answered
plese solve it as soon as possible
Asked by jayantkaushik | 07 Sep, 2009, 06:18: PM
Expert Answer
f(x) = 6x3 - 11x2 + kx - 20
f(4/3) = 0.
6(4/3)3 - 11(4/3)2 + k(4/3) - 20 = 0
6(64/27) - 11(16/9) + k(4/3) - 20 = 0
k(4/3) = 20(27)/27 + 11(3)(16/27) - 6(64/27)
k(4/3) = [20(27) + 11(3)(16) - 6(64)]/27
k = 19.
Regards,
Team,
TopperLearning.
Answered by | 07 Sep, 2009, 07:08: PM
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