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Asked by vivek1011 12th September 2009, 11:19 PM
Answered by Expert
Answer:

Assume,

L = Length of the wire,

A = Cross sectional area of the wire,

ρ = Resistivity of the wire,

R = Resistance of the wire,

R = ρL/A

R' =  Resistance of 1 part = (ρL)/(5A)

1/Req = 5(1/R') = 5 (5A)/(ρL)

1/Req = (25A)/(ρL)

Req = (ρL)/(25A)

R/Req = 25

Regards,

Team,

TopperLearning.

Answered by Expert 13th September 2009, 1:21 AM
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