Please wait...
Contact Us
Contact
Need assistance? Contact us on below numbers

For Study plan details

10:00 AM to 7:00 PM IST all days.

Franchisee/Partner Enquiry (North)

Franchisee/Partner Enquiry (South)

Franchisee/Partner Enquiry (West & East)

OR

or

Thanks, You will receive a call shortly.
Customer Support

You are very important to us

For any content/service related issues please contact on this number

8788563422

Mon to Sat - 10 AM to 7 PM

Please solve this sum

qsnImg
Asked by pukai7229 28th October 2018, 11:18 PM
Answered by Expert
Answer:
Let length LS of measuring steel scale at 0°C = 100 cm.
Length LZ of zinc rod at 0°C = 100 cm.
 
actual length of steel scale at 100°C = LS(1 + αS × ΔT) = 100(1+1.2×10-5×100) = 100.12 cm
actual length of zinc rod at 100°C = LZ(1 + αZ × ΔT) = 100(1+2.6×10-5×100) = 100.26 cm
 
where αS and αZ are linear thermal expansion coefficient of steel and zinc respectively.
 
Zinc rod has expanded more than steel scale.
If the expanded zinc rod is measured using expanded steel rod, then the ratio is = 100.26/100.12 = 1.001398
 
Hence 0.001398 part of zinc rod is measured again by same expanded steel scale.
Then the measured length of remaining part = 100.12×0.001398 = 0.14 cm
 
Hence the measured value by expanded steel scale = 100+0.14 = 100.14 cm
Answered by Expert 29th October 2018, 7:12 AM
Rate this answer
  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10

You have rated this answer /10

Your answer has been posted successfully!

Chat with us on WhatsApp