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Please solve this question

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Asked by brijk456 11th August 2019, 12:29 AM
Answered by Expert
Answer:
Let initial velocity be v and kinetic energy (1/2)mv2
 
if velocity increased by 2 m/s, then kinetic energy (1/2) m (v+2)2
 
It is given that kinetic energy is doubled by increased velocity, i.e., (v+2)2 = 2v2  ................. (1)
 
eqn.(1) is simplified as, v2 - 4v - 4 = 0  ................ (2)
 
Roots of qutratic eqn.(2),  v = 2±2√2    and realistic initial velocity is  (2+2√2) m/s   or  2(1+√2) m/s
Answered by Expert 11th August 2019, 8:11 AM
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