NEET Class neet Answered
Please solve this question
Asked by brijk456 | 11 Aug, 2019, 12:29: AM
Expert Answer
Let initial velocity be v and kinetic energy (1/2)mv2
if velocity increased by 2 m/s, then kinetic energy (1/2) m (v+2)2
It is given that kinetic energy is doubled by increased velocity, i.e., (v+2)2 = 2v2 ................. (1)
eqn.(1) is simplified as, v2 - 4v - 4 = 0 ................ (2)
Roots of qutratic eqn.(2), v = 2±2√2 and realistic initial velocity is (2+2√2) m/s or 2(1+√2) m/s
Answered by Thiyagarajan K | 11 Aug, 2019, 08:11: AM
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