CBSE Class 10 Answered
Please solve this question
Asked by vikasg13.hardware | 30 Jun, 2018, 07:09: AM
Expert Answer
We have following standard results:
1) If O is the circumcentre of triangle ABC then angle subtended by BC at O is twice the angle subtended at A. So that angle BOC=2 angle BAC
2) If H is the orthocentre then angle made by BC at H and angle BAC are supplementary. Thus angle BHC+ angle BAC =180
3) If I is the incentre then angle BIC = 90+A/2
4) Angle made in the same side of the arc of the circle are equal.
We have been given that H, I, B, C are on the same circle
Thus BHC=BIC (from property 4)
Thus 180-BAC=90+A/2 (Using property 2 and 3)
Or 90=BAC+BAC/2=3BAC/2
Thus BAC=2*90/3=60
Hence BOC=2BAC=2*60=120(Using property 1 and the above result)
Answered by Arun | 10 Jul, 2018, 10:18: AM
Application Videos
Concept Videos
CBSE 10 - Maths
Asked by pathakvaishnavi9139 | 23 Mar, 2024, 10:45: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by mustafahssn786 | 23 Mar, 2024, 06:25: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by choudharyniki001 | 22 Mar, 2024, 08:49: AM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by jagdishdabang79 | 18 Mar, 2024, 08:40: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by vn3950372 | 18 Mar, 2024, 08:38: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by vestigevestige85 | 17 Mar, 2024, 09:44: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by jayashreelatha04 | 17 Mar, 2024, 05:38: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by suvarnaapkare | 15 Mar, 2024, 04:59: PM
ANSWERED BY EXPERT
CBSE 10 - Maths
Asked by anubhutiupadhaya | 15 Mar, 2024, 03:33: PM
ANSWERED BY EXPERT