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Asked by vikasg13.hardware | 30 Jun, 2018, 06:55: AM
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begin mathsize 16px style In space increment APQ sinθ equals fraction numerator straight y over denominator straight x plus 10 end fraction........ left parenthesis straight I right parenthesis In space increment AA apostrophe straight B sinθ equals fraction numerator 5 over denominator 2 straight x end fraction............ left parenthesis II right parenthesis fraction numerator straight y over denominator straight x plus 10 end fraction equals fraction numerator 5 over denominator 2 straight x end fraction........ left parenthesis III right parenthesis space space from space left parenthesis straight I right parenthesis space and space left parenthesis II right parenthesis Similarly fraction numerator straight y over denominator straight x minus 10 end fraction equals fraction numerator 15 over denominator 2 straight x end fraction........ left parenthesis IV right parenthesis 5 straight x space plus space 50 space equals space 15 straight x space minus space 150........ from space left parenthesis III right parenthesis space and space left parenthesis IV right parenthesis Solving space this space we space get straight x equals 20 Radius space of space straight capital omega subscript 1 space is space 20 end style
Answered by Sneha shidid | 06 Jul, 2018, 09:54: AM

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CBSE 10 - Maths
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