NEET Class neet Answered
Please solve this problem
Asked by Www.manashjyoti333 | 09 Nov, 2019, 09:01: PM
Expert Answer
Figure shows the tension force acting on the wire at A ( lowest position) and also at B (top most posiion )
At top most position B, we have , Tt + mg = ( mvt2 )/R .................(1)
Tension in wire when the mass is at B, Tt = ( mvt2 )/R - mg ...............(2)
To complete the circular motion in vertical plane, Tt = [ ( mvt2 )/R - mg ] ≥ 0 or vt2 ≥ ( R g ) ........................(3)
Let vo be the velocity of circulating mass at position A.
By conservation of energy, we have, (1/2)mvo2 = (1/2)m vt2 + (m g 2R) ......................(4)
Using eqn.(3) and eqn.(4), vo2 = 5gR ............................(5)
Strain in the wire when the mass is at A is given by, Y = ( Tb / A ) / Strain ....................(6)
where Y is Young's modulus , Tb is tension in the wire and A is area of cross section of wire
at position-A, by force balance, we have, Tb - mg = ( m vo2 /R ) .................(7)
Using, eqns.(5), (6) and (7), we get, Strain = 6mg / ( A Y )
Answered by Thiyagarajan K | 10 Nov, 2019, 08:29: AM
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