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Please solve the problem in the image immediately... provide the steps.
Asked by miaowmira1900 | 15 Aug, 2019, 05:39: PM
Expert Answer
Step-1
Let us open the current source and the circuit after opening the current source is shown above.
Current through the circuit = 10 V / 7Ω = (10/7) A
Voltage across 4Ω resistance = (10/7) A × 4Ω = (40/7) V ..................................(1)
Step-2
Now let us short the voltage source. Circuit after shorting the voltage source is given above in left most figure.
In the circuit we have two current sources. Let us find the voltage across 4Ω resistor independently,
hence first open the current source 0.5Vo and the circuit is shown at middle figure.
As shown in right most figure, the effective circuit is parallel combination of 2Ω and (4Ω+1Ω) is connected across current source
Current passing through (4Ω+1Ω) resistors is (2×2)/(4+1+2) = 4/7A
Hence voltage across 4Ω resistance due to this current = 4×(4/7) = 16/7 V ..................................(2)
Step-3 :-
Now let us open the current source 2A. Resulting circuit is shown in middle.
The efective circuit is shown in right most figure.
As shown in right most figure, a parallel combination of 1Ω and (4Ω+2Ω) is connected across 0.5Vo current source .
Current through the (4Ω+2Ω) resistors is 0.5Vo ×(1/7) = ( Vo/14) A
Hence voltage across 4Ω resistance = ( Vo/14) A × 4 = (2/7)Vo ...............................(3)
from eqn.(1), (2) and (3), we get , (40/7)+(16/7) + (2/7)Vo = Vo or (5/7)Vo = 56/7 or Vo = 11.2 V
Answered by Thiyagarajan K | 15 Aug, 2019, 10:19: PM
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