JEE Class main Answered
Please solve the problem
Asked by miaowmira1900 | 10 Sep, 2019, 04:18: AM
Expert Answer
Amplitude Ar of reflected wave :-
where Ai is amplitude of incident wave, v1 is velocity in string-1 (incident wave string ) and v2 is velocity in string-2
Amplitude At of transmitted wave :-
frequency in both the strings are same.
wavelength in string-1 is 1 cm . let wave length in string is x cm
then we have, ( v1 / 1 ) = ( v2 / x ) or x = ( v2 / v1 ) = 10/15 ≈ 0.67 cm
Hence size of transmitted pulse (h, w) :- ( 4 mm, 0.67 cm )
Hence size of reflected pulse (h, w) :- ( -1 mm, 1 cm )
Answered by Thiyagarajan K | 10 Sep, 2019, 02:34: PM
Application Videos
JEE main - Physics
Asked by arivaryakashyap | 23 Apr, 2024, 10:40: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ratnadeep.dmr003 | 21 Apr, 2024, 11:06: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by ksahu8511 | 19 Apr, 2024, 11:55: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by mohammedimroz | 13 Apr, 2024, 09:48: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by medhamahesh007 | 02 Apr, 2024, 11:11: AM
ANSWERED BY EXPERT
JEE main - Physics
Asked by gundlasumathi93 | 31 Mar, 2024, 02:13: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by chhayasharma9494 | 31 Mar, 2024, 12:47: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by archithateja3 | 30 Mar, 2024, 10:23: PM
ANSWERED BY EXPERT
JEE main - Physics
Asked by Machinenineha | 27 Mar, 2024, 05:28: PM
ANSWERED BY EXPERT