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CBSE Class 12-science Answered

Please solve the following question
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Asked by Balbir | 07 Feb, 2018, 12:32: PM
answered-by-expert Expert Answer
Net EMF that driving current through the circuit is 8-4 = 4V.
 
Effective resistance between A and B  due to parallel combinatin of 3Ω and 6Ω  = (3×6)/(3+6) = 2Ω
 
net resistance in the circuit = 0.5+4.5+2+1 = 8Ω. Hence current in the circuit is 4/8 = 0.5A
 
0.5A will flow through 0.5Ω, 4.5Ω and 1Ω.
 
potential difference across resistors connected in parallel = 0.5×2 = 1V.
 
hence current through 3Ω is (1/3) A and current through 6Ω is (1/6)A

A concave lens always gives a virtual, erect and diminished image. Hence, the lens used by the second student is the one which will give such an image.

Answered by Thiyagarajan K | 07 Feb, 2018, 03:07: PM

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CBSE 12-science - Physics
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