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Please solve the following question

Asked by Balbir 7th October 2017, 11:01 PM
Answered by Expert
Answer:
begin mathsize 16px style integral fraction numerator dx over denominator fourth root of 1 plus straight x to the power of 4 end root end fraction
fraction numerator begin display style fourth root of 1 plus straight x to the power of 4 end root end style over denominator straight x end fraction equals straight t
using space division space rule space of space derivative space
dx equals fraction numerator 1 over denominator begin display style fraction numerator straight x squared over denominator begin display style open parentheses 1 plus straight x to the power of 4 close parentheses to the power of 3 over 4 end exponent end style end fraction minus fraction numerator begin display style fourth root of 1 plus straight x to the power of 4 end root end style over denominator straight x squared end fraction end style end fraction dt
integral fraction numerator negative straight t squared over denominator straight t to the power of 4 minus 1 end fraction dt
minus integral fraction numerator begin display style straight t squared end style over denominator begin display style open parentheses straight t plus 1 close parentheses open parentheses straight t minus 1 close parentheses open parentheses straight t squared plus 1 close parentheses end style end fraction dt
Using space partial space fraction space you space can space solve space it space further.
end style
Answered by Expert 18th December 2017, 10:51 AM
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