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# Please solve the below question with whole steps

Asked by pranavalwar 29th September 2009, 8:52 PM

Gram molecular mass of Al2O3 = 2 x 27 + 3  x 16 =  102 g

One molecule of Al2O3 has   =     two  Al3+ ions

Multiplying both sides by NA (Avogadro's number).

NA molecules of Al2O3 has   =    2 x NA  Al3+ ions

Since 1 mole of a molecule contains NA molecules

1 mole of Al2O3 has   =  2 x NA  Al3+ ions

Since the mass of 1 mole of a molecule is gram molecular  mass

GMM of   Al2O3 has    = 2 x 6.023 x 1023  Al3+ions

102 g of   Al2O3 has    = 2 x 6.023 x 1023  Al3+ions

102 g of   Al2O3 has   = 12.046 x 1023  Al3+ions

Answered by Expert 30th September 2009, 2:02 PM
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