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Home / Doubts and Solutions/JEE/Mathematics

please solve the 7th one
 

Asked by jaychandran1967 2nd December 2017, 10:40 PM
Answered by Expert
Answer:
begin mathsize 16px style straight x to the power of square root of straight x end exponent equals open parentheses square root of straight x close parentheses to the power of straight x Taking space log space on space both space sides comma log straight x to the power of square root of straight x end exponent equals log open parentheses square root of straight x close parentheses to the power of straight x square root of straight x logx equals xlog square root of straight x square root of straight x logx equals straight x over 2 logx open parentheses square root of straight x minus straight x over 2 close parentheses logx equals 0 Either space logx equals 0 space rightwards double arrow straight x equals 1 or space open parentheses square root of straight x minus straight x over 2 close parentheses equals 0 rightwards double arrow straight x equals 4 Hence comma space they space are space relatively space prime. They space are space not space twin space prime space as space their space difference space is space not space 2. They space are space coprime. Here comma space log subscript 4 1 space equals 0 space yes space it space is space defined space but space log subscript 1 4 space is space not space defined. Correct space options space are space straight A comma space straight C space and space straight D. end style
Answered by Expert 5th December 2017, 12:27 PM
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